WebSep 28, 2024 · There is not a specific answer to this question as stated. (Assuming that this is in 3d space, as the coordinates list three values.) Technically, there are infinite perpendicular lines rotated around the black line. If you have a third point, you can use the Cross Product to get a perpendicular vector, like:

VECTORS: Foot of Perpendicular from Point to Line - YouTube

WebApr 7, 2024 · As the foot of the perpendicular must lie on the line, we should use the relation direction ratios of the perpendicular and that of the line to obtain the point of intersection. Then, as the point of intersection … WebMar 30, 2024 · Transcript. Question 37 (Choice 2) Find the foot of the perpendicular drawn from the point (−1, 3, −6) to the plane 2𝑥 + 𝑦 − 2𝑧 + 5 = 0. Also find the equation and length of the perpendicular. Let point P (x1, y1, z1) be foot of perpendicular from point X (−1, 3, −6) Since perpendicular to plane is parallel to normal vector ... hughes oshkosh hours

Ex 11.3, 4 (a) - Find the coordinates of foot of …

WebIf M ( x 2, y 2) is the foot of a perpendicular drawn from P ( x 1, y 1) on the line a x + b y + c = 0, then. x 2 − x 1 a = y 2 − y 1 b = − ( a x 1 + b y 1 + c) a 2 + b 2. This is given as a formula in my module without any explanation. … WebEquation and Foot of a Perpendicular from a point on the line Method to find the equation and foot of the perpendicular from a point on the line: 1. The given point is (p, q, r) and … WebWhen two planes are perpendicular, the dot product of their normal vectors is 0. Hence, 4a-2=0 \implies a = \frac {1} {2}. \ _ \square 4a−2 = 0 a = 21. . What is the equation of the plane which passes through point A= (2,1,3) … hughes organic farm